4y^2-3y^3-7y^2=6y^3

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Solution for 4y^2-3y^3-7y^2=6y^3 equation:


Simplifying
4y2 + -3y3 + -7y2 = 6y3

Reorder the terms:
4y2 + -7y2 + -3y3 = 6y3

Combine like terms: 4y2 + -7y2 = -3y2
-3y2 + -3y3 = 6y3

Solving
-3y2 + -3y3 = 6y3

Solving for variable 'y'.

Combine like terms: -3y3 + -6y3 = -9y3
-3y2 + -9y3 = 6y3 + -6y3

Combine like terms: 6y3 + -6y3 = 0
-3y2 + -9y3 = 0

Factor out the Greatest Common Factor (GCF), '-3y2'.
-3y2(1 + 3y) = 0

Ignore the factor -3.

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(1 + 3y)' equal to zero and attempt to solve: Simplifying 1 + 3y = 0 Solving 1 + 3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3y = 0 + -1 3y = 0 + -1 Combine like terms: 0 + -1 = -1 3y = -1 Divide each side by '3'. y = -0.3333333333 Simplifying y = -0.3333333333

Solution

y = {0, -0.3333333333}

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